Ok, so I am attempting to calc this at least. Basically Hal Jordan sends out an SOS signal in the form of some missiles but they return because no Green Lanterns exist in his universe anymore apparently. This means they searched the entire universe in a heartbeat. So I need to quantify how much they searched in that time. We know there are at least four of them.
Feat comes from Green Lantern volume 2 issue 63:
Based on a Megaman.EXE calc this feat becomes much more difficult because this is based on missiles and Megaman.EXE can have a somewhat human field of view, unlike a missile. Missiles don't normally travel the volume of the universe so this was somewhat difficult to reconcile with.
I'm going to use 72 beats per second for the heartbeat, which I've found is the average based on some google searches and it appears to be within a healthy heartrate range for adults, between 60 to 100 bpm. My heartrate is also 72 bpm. The second answer on this question uses 72 bpm: https://www.quora.com/How-many-times-does-our-heartbeat-in-1-second
It is close to an average value between 60 and 100 anyway, so that aside, this means our timeframe is 0.833 seconds. Remember it could be higher or lower. Our lower and higher bound are 0.6 and 1 second.
I found the DC universe diameter here. I will use the 100 trillion LY universe as we know it if I must as well for lower ends.
This gives us 2.465355435982e45 km of course as our diameter. I did not provide a scan but the 60 trillion LY in a half second thing is here:
The expansion of space is quicker than that of light, remember. So it could be higher than this if the study that won a Nobel prize for the universe's expansion speeding up is correct, which most believe it is.
Missiles use telescopes to find their target, but how far a telescope on a GL construct can see is really dubious so I will go with max human visibility which VS Battles Wiki found after numerous content revision threads to be 20 kilometers:
https://vsbattles.fandom.com/wiki/User_blog:Mr._Bambu/Bloodstained_Calc:_Tornado_Storm
Let's define its vision as a cylinder. 20 kilometers in radius for this cylinder, since thats how far it should see on any given side, with its height as tall as this universe is. Plugging that into google gives us 3.1e48 km^3 as our volume.
Now with my 2.465355435982e45 km universe diameter, if we are to define the universe as a sphere, which many do, then the volume of a sphere this gives us, with a halved km value for our radius of course, gives us a volume for the DC universe as 7.85e135 km^3.
Too big for a lot of calculators, so doing it manually, law of indices says a^m / a^n = a^m - n. 2.532258e90 is the number of times this trip is made, assuming the entire universe is covered.
For the final part: universe diameter * the number of times the trip is made.
2.465355435982e45 km * 2.532258e90 = 6.2429e135 km
Now for timeframes:
- 6.2429e135 / 0.6 sec = 1.040486e136 km/s
- 6.2429e135 / 0.8333 sec = 7.49148e135 km/s
- 1 sec is obviously 6.2429e135 km/s
SOL is 299792458 m/s, 299,792.458 km/s in other words.
- Low end: 2.082407e130c, 20.8 duoquadragintillion times FTL
- Mid end: 2.498888747e130c, 24.988 duoquadragintillion times FTL
- High end: 3.4706877e130c, 34.706 duoquadragintillion times FTL
Beyond a googol times FTL, but if you just want 100 trillion LY as your radius then okie dokie, I guess, let's try that.
1.89214609451616e27 kilometers is our diameter, making our volume, if we define our universe as a sphere of course, 3.55e81 km^3.
So all we need to adjust for that cylinder thing if we define their field of vision as a cylinder is of course the diameter we use.
Our cylinder volume takes a hit and becomes 2.38e30 km^3. Divvy the universe volume by cylinder volume and we get 1.491e51 trips.
Finally, trips times universe diameter.
1.491e51 * 1.89214609451616e27 = 2.8223e78 km
Now our timeframes one last time.
- 2.8223e78 km / 0.6 sec = 4.703864590709e78 km/s
- 2.8223e78 km / 0.833 sec = 3.386760013547e78 km/s
- 2.8223e78 km / 1 sec = 2.8223e78 km/s to no one's surprise
So this gives us: 299,792.458
- Low end: 9.414179458777e72c, 9.414 trevigintillion times FTL
- Mid end: 1.129701539572e73c, 11.297 trevigintillion times FTL
- High end: 1.569040336134e73c, 15.690 trevigintillion times FTL
So:
- Low universe size, low end: 9.414 trevigintillion c
- Low universe size, mid end: 11.297 trevigintillion c
- Low universe size, high end: 15.690 trevigintillion c
- High universe size, low end: 20.8 duoquadragintillion c
- High universe size, mid end: 24.988 duoquadragintillion c
- High universe size, high end: 34.706 duoquadragintillion c
We actually are not done yet, we need to divide all of these by 4 since there were at least 4 missiles presumably doing equal work.
- Low universe size, low end: 2.3535 trevigintillion c
- Low universe size, mid end: 2.82425 trevigintillion c
- Low universe size, high end: 3.9225 trevigintillion c
- High universe size, low end: 5.2 duoquadragintillion c
- High universe size, mid end: 6.247 duoquadragintillion c
- High universe size, high end: 8.6765 duoquadragintillion c